Write a program in python to check a number is Armstrong or not.

Program for Check a number is Armstrong or not.

Before start the programming, we need to know that, what is Armstrong Number?

An Armstrong number is a number such that the sum of its all digits raised to the power of 'total no of digit' is equal to the number itself

Steps of programming:-

1. get input from user (e.g- int x).
2. Store that no in another variable because after calculation we need to compair the calculated value to the inputted value (e.g- y=x).
3. initialize two variable with zero (0) because we will store result in these variable during the loop (e.g- a=0 & z=0).
4. Calculate length of inputted integer value (e.g- let 'l' is length)
5. Start a loop till inputted value becomes zero  and  decrements with divided by 10 (means x=x/10).
6. In loop calculate mod (%)10 of inputted value and store in a variable which is initialize with zero (e.g- z=x%10).
7. And after it calculate z*i and store in another variable (e.g- a=a+(z**i)).
8. Then we compare the calculated value to the inputted value if both are same then we can say that the inputted value is Armstrong else not.

code:-

x=int(input("Enter number : "))
y=x
a=0
z=0
l=len(str(x))
while x!=0:
    z=x%10
    a=a+(z**l)     
    x=x//10
if y==a:
     print(y,"is an armstrong number")
else: 
    print(y,"is not an armstrong number")

What will be done in the loop section ?

In the loop section means after while statement, 1st it will check, is x is zero or not, if x =0 then loop will break else z=x%10 and after it a=a+(z**l) means in 'a' it will store l'th power of z and then x=x//10. after it loop will start again and check is x = 0 if not then work again till x=0. 

#DizIT_Operators

Thank-you